t^2*16-128t-t*2+16=0

Solution for t^2*16-128t-t*2+16=0 equation:

t^2*16-128t-t*2+16=0

Wy multiply elements

16t^2-128t-2t+16=0

We add all the numbers together, and all the variables

16t^2-130t+16=0

a = 16; b = -130; c = +16;
Δ = b2-4ac
Δ = -1302-4·16·16
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-126}{2*16}=\frac{4}{32}
=1/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+126}{2*16}=\frac{256}{32}
=8
$